C166: Warning C192 (Value Truncated)

Information in this article applies to:

• C166 Version 4.25, or newer

QUESTION

With my C166 package, I sometimes receive the following message:

Warning C192: Value Truncated

The following example causes this warning:

unsigned char v;
unsigned char s;

v = (s & 0x0F) | ((s + 1) << 4) | 0x88;

The code still works. So, what does this warning mean and is it serious?

ANSWER

Warning C192 is issued because your statement generates a potential int value and the result gets truncated by the assignment to an unsigned char.

Avoid this warning with an explicit type cast like:

v = (unsigned char) ((s & 0x0F) | ((s + 1) << 4) | 0x88);

SEE ALSO

• GENERAL: #DEFINEs With Arithmetic Don't Work

Last Reviewed: Thursday, February 25, 2021