The __align keyword instructs the compiler to align a variable on an n-byte boundary.
__align is a storage class modifier. It does not affect the type of the function.
Syntax
__align(n)
Where:
n
is the alignment boundary.
For local variables, n can take the values 1, 2, 4, or 8.
For global variables, n can take any value up to 0x80000000 in powers of 2.
Usage
__align(n) is useful when the normal alignment of the variable being declared is less than n. Eight-byte alignment can give a significant performance advantage with VFP instructions.
__align can be used in conjunction with extern and static.
Restrictions
Because __align is a storage class modifier, it cannot be used on:
types, including typedefs and structure definitions
function parameters.
You can only overalign. That is, you can make a two-byte object four-byte aligned but you cannot align a four-byte object at 2 bytes.
Examples
__align(8) char buffer[128]; // buffer starts on eight-byte boundary
void foo(void)
{
...
__align(16) int i; // this alignment value is not permitted for
// a local variable
...
}
__align(16) int i; // permitted as a global variable.